WAEC - Mathematics (2007 - No. 44)

Find the value of a if log\(_{10}\) a + log\(_{10}\)a\(^2\) = 0.9030
4.0
2.0
1.6
0.0

Explanation

log\(_{10}\) a + log\(_{10}\)a\(^2\) = 0.9030

log (a x a\(^2\)) = 0.9030

log a\(^3\) = 0.9030

a\(^3\) = 10^.9030(antilogarithm table)

a\(^3\) = 7.998

a = 3\(\sqrt{7.998}\)

a = 1.9998 ≈ 2.0

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