WAEC - Mathematics (2006 - No. 39)

In the diagram, P, Q and R are three points in a plane such that the bearing of R from Q is 110^o and the bearing of Q from P is 050^o. Find angle PQR.

60^o

70^o

120^o

160^o

Explanation

Q₁ = 50(alternate angle)

Q₂ = 180^o - 110^o (straight line angle)

Q₂ = 70

PQR = Q₁ + Q₂

= 50^o + 70^o

= 120^o

WAEC - Mathematics (2006 - No. 39)

Explanation

Comments (0)