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WAEC - Mathematics (2006 - No. 37)
In the diagram, PR is a diameter of the circle centre O. RS is a tangent at R and QPR = 58
o
. Find < QRS
112
o
116
o
122
o
148
o
Explanation
PRQ = 90 - 58 = 32
o
(angle in a semi-circle)
Since PRS = 90
o
(radius angular to tangent)
QRS = 90 + 32
= 122
o
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