WAEC - Mathematics (2005 - No. 36)
For what values of y is the expression \(\frac{6y-1}{y^2 - y-6}\) not defined?
\(\frac{1}{6}, \frac{1}{4}\)
3, -2
-3, 2
0,1
Explanation
The expression is not defines when \(y^2\) - y - 6 = 0
=> \(y^2\) - 3y + 2y - 6 = 0 => (y-3)(y+2) = 0 => y
-3 = 0 or y + 2 = 0 => y = 3 or -2
=> \(y^2\) - 3y + 2y - 6 = 0 => (y-3)(y+2) = 0 => y
-3 = 0 or y + 2 = 0 => y = 3 or -2
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