WAEC - Mathematics (2004 - No. 39)
The diagram is a circle centre O. Find the value of x
30o
50o
61o
78o
65.5\(^{\circ}\)
Explanation
∠PQR (Reflex) = 360° – 68° = 292°
∠PQR = 2∠PQR
292° = 4x + 30°
4x = 292 – 30 = 262
\(x = \frac{262}{4}=65.5°\)
∠PQR = 2∠PQR
292° = 4x + 30°
4x = 292 – 30 = 262
\(x = \frac{262}{4}=65.5°\)
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