WAEC - Mathematics (2004 - No. 12)
Given that x + y = 7 and 3x-y = 5, evaluate \(\frac{y}{2}-3\).
-1
1
3
4
Explanation
\(x + y = 7 ------ I\\
3x – y = 5 ------ II\)
Add I and II;
\(4x = 12 => x = \frac{12}{4} = 3\\
Y = 7 – 3 = 4, evaluate \hspace{1mm} \frac{y}{2} – 3\\
\frac{4}{2} – 3 => 2-3 = -1\)
3x – y = 5 ------ II\)
Add I and II;
\(4x = 12 => x = \frac{12}{4} = 3\\
Y = 7 – 3 = 4, evaluate \hspace{1mm} \frac{y}{2} – 3\\
\frac{4}{2} – 3 => 2-3 = -1\)
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