WAEC - Mathematics (2003 - No. 43)
A right circular cone is such that its radius r is twice its height h. Find its volume in terms of h
\(\frac{2}{3}\pi h^2\)
\(\frac{1}{12}\pi h^3\)
\(\frac{4}{3}\pi h^2\)
\(\frac{4}{3}\pi h^3\)
Explanation
Volume of a cone = \(\frac{\pi r^2 h}{3}\)
r = 2h.
V = \(\frac{\pi \times (2h)^2 \times h}{3}\)
= \(\frac{4}{3} \pi h^3\)
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