WAEC - Mathematics (2002 - No. 45)

In the diagram O is the center of the circle, ∠SOR = 64° and ∠PSO = 36°. Calculate ∠PQR

100^o

96^o

94^o

86^o

< OSR = < ORS = \(\frac{180° - 64°}{2}\) = 58°

< PSR = 36° + 58° = 94°

< PSR + < PQR = 180°

94° + < PQR = 180° \(\implies\) < PQR = 180° - 94° = 86°