WAEC - Mathematics (2002 - No. 4)
In the diagram above, ∠PQU=36°, ∠QRT = 29°, PQ||RT. Find ∠PQR
94o
65o
61o
54o
Explanation
< UQR = 29° (alternate angles)
< PQR = < PQU + < UQR
= 36° + 29°
= 65°
Comments (0)
In the diagram above, ∠PQU=36°, ∠QRT = 29°, PQ||RT. Find ∠PQR
< UQR = 29° (alternate angles)
< PQR = < PQU + < UQR
= 36° + 29°
= 65°
