WAEC - Mathematics (2002 - No. 23)
The lengths of the parallel sides of a trapezium are 9 cm and 12 cm. lf the area of the trapezium is 105 cm2, find the perpendicular distance between the parallel sides.
5cm
7cm
10cm
15cm
Explanation
\(\frac{1}{2}(a+b)\times h = 105cm^2\\
\frac{1}{2}(9+12)\times h = 105\\
h = \frac{105 \times 2}{21} = 10cm\)
\frac{1}{2}(9+12)\times h = 105\\
h = \frac{105 \times 2}{21} = 10cm\)
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