WAEC - Mathematics (2001 - No. 2)
Evaluate \((20_{three})^2 - (11_{three})^2\) in base three
101
121
202
2020
Explanation
\((20_{three})^2 - (11_{three})^2\)
= \((20_{3} - 11_{3})(20_{3} + 11_{3})\)
= \((2_{3})(101_{3})\)
= \(202_{3}\)
Comments (0)
\((20_{three})^2 - (11_{three})^2\)
= \((20_{3} - 11_{3})(20_{3} + 11_{3})\)
= \((2_{3})(101_{3})\)
= \(202_{3}\)
