WAEC - Mathematics (2000 - No. 28)

Given that \(27^{(1+x)}=9,)\ find x

-3

\(\frac{-1}{3}\)

\(\frac{5}{3}\)

\(27^{(1+x)}\) = 9
\(3^{3(1+x)} = 3^2\)
3(1+x) = 2
3 + 3x = 2
3x = -1

x = \(\frac{-1}{3}\)