WAEC - Mathematics (1999 - No. 34)
The root of a quadratic equation in x, are -m and 2n. Find the equation
\(x^2 + x(m - 2n)-2mn=0\)
\(x^2 - x(m - 2n)-2mn=0\)
\(x^2 - x(m - 2n)+2mn=0\)
\(x^2 + x(m - 2n)+2mn=0\)
Explanation
x = -m \(\implies\) x + m = 0;
x = 2n \(\implies\) x - 2n = 0.
\(\implies (x + m)(x - 2n) = 0\)
\(x^2 + mx - 2nx - 2mn = 0\)
\(x^2 + x(m - 2n) - 2mn = 0\)
Comments (0)
