WAEC - Mathematics (1998 - No. 49)
In \(\triangle PQR\). T is a point on QR such that \(\angle QPT = 39^o and \angle PTR = 83^o. Calculate \angle PQT\)
\(34^o\)
\(44^o\)
\(45^o\)
\(97^o\)
\(107^o\)
Explanation
In △ PQR, < PQT + 39º = 83º (sum of opposite interior <s)
Therefore, < PQT = 83º - 39º = 44º.
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