WAEC - Mathematics (1998 - No. 41)

In the diagram PQ is a diameter of circle PMQN center O, if ∠PQM = 63o, find ∠MNQ

58.5^o

44^o

35^o

31.5^o

27^o

In the given diagram,

< PMQ = 90º (< in a semi-circle)

<QPM = 180º - ( 90 + 63 )º = 27º

Therefore, <MNQ = <QPM = 27º ( <s in same segment)