WAEC - Mathematics (1998 - No. 13)
Simplify \(\frac{8^{\frac{2}{3}}*27^{\frac{-1}{3}}}{64^{\frac{1}{3}}}\)
-3
\(\frac{1}{9}\)
\(\frac{1}{3}\)
\(\frac{27}{8}\)
4
Explanation
\(\frac{8^{\frac{2}{3}}*27^{\frac{-1}{3}}}{64^{\frac{1}{3}}}\)
\(\frac{2^2*3^{-3}}{4} = 3^{-1} = \frac{1}{3}\)
\(\frac{2^2*3^{-3}}{4} = 3^{-1} = \frac{1}{3}\)
Comments (0)
