WAEC - Mathematics (1997 - No. 4)
A student found the approximate value of 0.02548 correct to two places of decimal instead of two significant figures. Find the percentage error.
0%
131/3%
15 5/13%
2/3%
20%
Explanation
0.02548 \(\approxeq\) 0.03 (to 2 decimal places)
0.02548 \(\approxeq\) 0.025 (2 sig. figs)
Error = 0.03 - 0.025
= 0.005
% error = \(\frac{0.005}{0.025} \times 100%\)
= 20%
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