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WAEC - Mathematics (1997 - No. 30)
O is the centre of the circle PQRS. PR and QS intersect at T POR is a diameter, ∠PQT = 42
o
and ∠QTR = 64
o
; Find ∠QRT
68
o
64
o
42
o
32
o
22
o
.
Explanation
TQR = 90 - 42 = 48
o
QRT = 180 - (64 - 48)
= 180 - 112
= 68
o
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