WAEC - Mathematics (1997 - No. 30)

O is the centre of the circle PQRS. PR and QS intersect at T POR is a diameter, ∠PQT = 42o and ∠QTR = 64o; Find ∠QRT
68o
64o
42o
32o
22o.

Explanation

TQR = 90 - 42 = 48o
QRT = 180 - (64 - 48)
  = 180 - 112
 = 68o

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