WAEC - Mathematics (1995 - No. 42)
In the diagram above, ∠PRQ = 90°, ∠QPR = 30° and /PQ/ = 10 cm. Find y.
6cm
5cm
4cm
3cm
2cm
Explanation
\(\sin 30° = \frac{y}{10}\)
\(y = 10 \sin 30° = 10 \times 0.5 = 5 cm\)
Comments (0)
In the diagram above, ∠PRQ = 90°, ∠QPR = 30° and /PQ/ = 10 cm. Find y.
\(\sin 30° = \frac{y}{10}\)
\(y = 10 \sin 30° = 10 \times 0.5 = 5 cm\)
