WAEC - Mathematics (1995 - No. 33)

In the diagram above, PQ is parallel to TU, ∠PQR = 50°, ∠QRS = 86° and ∠STU = 64°. Calculate the value of x.

136^o

120^o

108^o

100^o

96^o

y = 86° - 50° [Alternate ∠s are equal]

y = 86° - 50° = 36°

a = y = 36° [Alternate ∠s]; b = 64° [Alternate ∠s;]

x = a + b = (36° + 64°)

=100°