WAEC - Mathematics (1994 - No. 4)
Which of the following is equal to \(\frac{72}{125}\)
\( \frac{2^3 \times 3^2}{5^3} \)
\( \frac{2^4 \times 3}{5^3} \)
\( \frac{2^3 \times 3}{5^3} \)
\( \frac{2^4 \times 3}{5^5} \)
\( \frac{2^2 \times 3^2 \times 4^2}{5^2} \)
Explanation
\(\frac{72}{125} = \frac{8 \times 9}{5 \times 5 \times 5}\)
= \(\frac{2^3 \times 3^2}{5^3}\)
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