The points P(-2, 3) and Q(2, 7) are on the line.

Gradient of the line = \(\frac{7 - 3}{2 - (-2)}\)

= \(\frac{4}{4}\)

= 1

y = x + b

To find the intercept, we have

7 = 2 + b or 3 = -2 + b.

Solving for b, we get b = 5.

\(\therefore\) The line is y = x + 5.