WAEC - Mathematics (1992 - No. 22)
In the diagram above, O is the center of the circle PQRS and ∠QPS = 36°. Find ∠QOS
36o
72o
108o
144o
288o
Explanation
< QOS = 2 < QPS (angle subtended at the centre)
\(\therefore\) < QOS = 2 x 36° = 72°
In the diagram above, O is the center of the circle PQRS and ∠QPS = 36°. Find ∠QOS
< QOS = 2 < QPS (angle subtended at the centre)
\(\therefore\) < QOS = 2 x 36° = 72°