WAEC - Mathematics (1992 - No. 22)

In the diagram above, O is the center of the circle PQRS and ∠QPS = 36°. Find ∠QOS

36o
72o
108o
144o
288o

Explanation

< QOS = 2 < QPS (angle subtended at the centre)

\(\therefore\) < QOS = 2 x 36° = 72°

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