WAEC - Mathematics (1991 - No. 8)
Solve the equation: 3a + 10 = a\(^2\)
a = 5 or a = 2
a = -5 or a = 2
a = 10 or a = 0
a = 5 or a = 0
a = 5 or a = -2
Explanation
3a + 10 = a\(^2\)
a\(^2\) - 3a - 10 = 0
a\(^2\) - 5a + 2a - 10 = 0
a(a - 5) + 2(a - 5) = 0
(a - 5)(a + 2) = 0
a = 5 or a = -2.
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