WAEC - Mathematics (1990 - No. 21)
Solve the equation 7y\(^2\) = 3y
y = 3 or 7
y = 0 or 7
y = 0 or 3/7
y = 0 or 9
y = 0 or 10
Explanation
7y\(^2\) = 3y
7y\(^2\) - 3y = 0
y(7y - 3) = 0
y = 0 or y = \(\frac{3}{7}\)
Comments (0)
7y\(^2\) = 3y
7y\(^2\) - 3y = 0
y(7y - 3) = 0
y = 0 or y = \(\frac{3}{7}\)
