WAEC - Mathematics (1988 - No. 35)

In the diagram above, PR is perpendicular from P to QS, PQ = 2cm, QR = 1cm and PR = RS. what is the size of the angle QPS?

135^o

105^o

90^o

75^o

60^o

\(\Delta RPS\) = Isosceles triangle

\(\therefore < RPS = \frac{180° - 90°}{2}\)

= 45°

In \(\Delta QPR\),\(\sin < QPR = \frac{1}{2}\)

= 30°

\(\therefore < QPS = 30° + 45° = 75°\)