P(-3, 5), The given line, 2x - 4y + 3 = 0

2x - 4y + 3 = 0 rearrange to the slope-intercept form

4y = 2x + 3, divide through by 4

y = \(\frac{1}{2}\) x + \(\frac{3}{4}\)

M\(_1\) = \(\frac{1}{2}\), then M\(_2\) = -2 (condition for perpendicularity)

y - y\(_1\) = M\(_2\)(x - x\(_1\))

y - 5 = -2(x - (-3))

y - 5 = -2x - 6

y - 5 + 6 + 2x = 0

y + 2x + 1 = 0 becomes the equation of the line.