WAEC - Further Mathematics (2023 - No. 9)
Given that M is the midpoint of T (2, 4) and Q (-8, 6), find the length of MQ .
\(√26 units\)
\(√28 units\)
\(√24 units\)
\(√30 units\)
Explanation
\(|MQ| = \frac{1}{2} |TQ|\)
\(|TQ| = √((y2 - y1)^2 + (x2 - x1)^2)\)
\(|TQ| = √((6 - 4)^2 + (-8 - 2)^2)\)
\(|TQ| = √(2^2 + (-10)^2)\)
\(|TQ| = √(4 + 100) = √104\)
\(|TQ| = 2√26 units\)
\(|MQ| = \frac{1}{2} |TQ| = 2 \times 2√26\)
∴ \(|MQ| = √26 units\)
\(|TQ| = √((y2 - y1)^2 + (x2 - x1)^2)\)
\(|TQ| = √((6 - 4)^2 + (-8 - 2)^2)\)
\(|TQ| = √(2^2 + (-10)^2)\)
\(|TQ| = √(4 + 100) = √104\)
\(|TQ| = 2√26 units\)
\(|MQ| = \frac{1}{2} |TQ| = 2 \times 2√26\)
∴ \(|MQ| = √26 units\)
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