WAEC - Further Mathematics (2022 - No. 40)
A particle of mass 3kg moving along a straight line under the action of a F N, covers a line distance, d, at time, t, such that d = t\(^2\) + 3t. Find the magnitude of F at time t.
0N
2N
3(2t + 3)N
6N
Explanation
F = m * a
d = t\(^2\) + 3t.
a = \(\frac{d^2d}{dt^2}\)
\(\frac{d[d]}{dt}\) = 2t + 3
\(\frac{d^2d}{dt^2}\) = 2m/s\(^2\)
a = 2m/s\(^2\)
F = m * a
F = 3 × 2 = 6N
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