WAEC - Further Mathematics (2021 - No. 8)
In how many ways can 8 persons be seated on a bench if only three seats are available?
100
125
336
427
Explanation
\(^3{P}_3\) = \(\frac{8!}{8-3}!\)
= \(\frac{(8 * 7 * 6 * 5)!}{5!}\)
= 336
Comments (0)
\(^3{P}_3\) = \(\frac{8!}{8-3}!\)
= \(\frac{(8 * 7 * 6 * 5)!}{5!}\)
= 336
