WAEC - Further Mathematics (2021 - No. 2)

For what range of values of x is x\(^2\) - 2x - 3 ≤ 0

{x: -1 ≤ x ≤ 3}

{ x: -3 ≤ x ≤ 1}

{ x: -3 ≤ x ≤ -1}

{ x: 1 ≤ x ≤ 3}

Let x\(^2\) - 2x - 3 = 0;

(x+1)(x-3) = 0

The zeros of the function are x = -1 and 3

The solution set is { x: -1 ≤ x ≤ 3}