Cos \(\theta\) = \(\frac{4(12) + (-5)(3)}{\sqrt{12^2 + (-5)^2}\sqrt{4^2 + 3^2}}\)

Cos\(\theta\) = \(\frac{48 - 15}{(\sqrt{189})(\sqrt{25})}\)

\(\theta = cos^{-1}\) (\(\frac{33}{61.28}\))

\(\theta\) = cos\(^{-1}\)0.5367

\(\theta\) = 59\(^o\)