WAEC - Further Mathematics (2019 - No. 30)
Evaluate \(\int^9_0 \sqrt{x} dx\)
3
9
18
27
Explanation
\(\int^9_0 \sqrt{x} dx\)
\(\frac{x^{\frac{1}{2}} + 1}{\frac{1}{2} + 1}\) |\(^9_0\)
\(\frac{2x^{\frac{3}{2}}}{3}\)|\(^9_0\)
= \(\frac{2(9)^{\frac{3}{2}}}{3}\)
= \(\frac{2(3)^3}{3}\)
= \(\frac{2 \times 27}{3}\)
= 2 x 9
= 18
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