WAEC - Further Mathematics (2019 - No. 29)
Find the coordinates of the centre of the circle 3x\(^2\) + 3y\(^2\) - 6x + 9y - 5 = 0
(-3. \(\frac{9}{2}\))
(-1. \(\frac{3}{2}\))
(1, - \(\frac{3}{2}\))
(3. -\(\frac{9}{2}\))
Explanation
\(\frac{3x^2}{3} + \frac{3y^2}{3} - \frac{6x}{3} + \frac{9y}{3} - \frac{5}{3}\) = 0
2gx = -2x, 2 fy = 3y
g = -1, f = \(\frac{3}{2}\)
Centre (1, - \(\frac{3}{2}\))
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