WAEC - Further Mathematics (2018 - No. 35)
A body of mass 28g, initially at rest is acted upon by a force, F Newtons. If it attains a velocity of \(5.4ms^{-1}\) in 18 seconds, find the value of F.
0.0082N
0.0084N
0.082N
0.084N
Explanation
\(F = mass \times acceleration\) but \(accl = \frac{v - u}{t}\)
\(\therefore F = m(\frac{v - u}{t})\)
\(Mass = 28g = 0.028kg\)
\(v = 5.4 ms^{-1}; u = 0; t = 18secs\)
\(\therefore F = 0.028(\frac{5.4 - 0}{18}) = 0.028 \times 0.3 = 0.0084N\)
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