WAEC - Further Mathematics (2018 - No. 28)

Calculate the standard deviation of 30, 29, 25, 28, 32 and 24.
2.0
2.8
3.0
3.2

Explanation

\(x\) \(x - \mu\) \((x - \mu)^{2}\)
24 -4 16
25 -3 9
28 0 0
29 1 1
30 2 4
32 4 16
\(\sum\) = 168   46

\(\mu = \frac{24+25+28+29+30+32}{6} = \frac{168}{8} = 28\)

\(S.D = \sqrt{\frac{\sum{(x - \mu)^{2}}}{n}} = \sqrt{\frac{46}{6}}\)

= \(\sqrt{7.67} \approxeq 2.8\)

Comments (0)

Advertisement