WAEC - Further Mathematics (2018 - No. 26)
Find the stationary point of the curve \(y = 3x^{2} - 2x^{3}\).
(1, 0)
(-1, 0)
(1, 1)
(-1, -1)
Explanation
\(y = 3x^{2} - 2x^{3}\)
\(\frac{\mathrm d y}{\mathrm d x} = 6x - 6x^{2} = 0 \implies 6x(1 - x) = 0\)
\(x = 0, 1\), when x = 1, y = 0.
when x = 1, y = 0.
The stationary point is (1, 0)
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