WAEC - Further Mathematics (2016 - No. 23)
Find the equation of the line which passes through (-4, 3) and parallel to line y = 2x + 5.
y = 2x + 11
y = 3x + 11
y = 3x - 5
y = 2x - 11
Explanation
The gradient of the line y = 2x + 5 ;
\(\frac{\mathrm d y}{\mathrm d x} = 2\)
\(\frac{y - 3}{x - (-4)} = \frac{y-3}{x+4} = 2\)
\(y - 3 = 2(x + 4) \implies y = 2x + 11\)
Comments (0)
