WAEC - Further Mathematics (2008 - No. 28)

Marks 2 3 4 5 6 7 8
No of students 5 7 9 6 3 6 4

The table above shows the distribution of marks by some candidates in a test. Find, correct to one decimal place, the mean of the distribution.

5.5
5.3
5.2
4.7

Explanation

Marks(\(x\) 2 3 4 5 6 7 8 Total
Frequency \(f\) 5 7 9 6 3 6 4 40
\(fx\) 10 21 36 30 18 42 32 189

Mean \(\bar{x} = \frac{\sum fx}{\sum f} = \frac{189}{40}\)

= \(4.725 \approxeq 4.7\)

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