WAEC - Chemistry (2017 - No. 25)
The number of atoms present in 2.5moles of a triatomic gas is equivalent to [1mole = \(6.02\times 10^{23}\)]
\(2.5\times 10^{23}\)
\(1.5\times 10^{23}\)
\(1.5\times 10^{24}\)
\(2.5\times 10^{24}\)
Explanation
1 mole = \(6.02 \times 10^{23}\)
2.5 moles = \(6.02 \times 10^{23} \times 2.5\)
= \(15.05 \times 10^{23} = 1.505 \times 10^{24}\)
\(\approxeq 1.5 \times 10^{24}\)
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