WAEC - Chemistry (2017 - No. 11)

The oxidation number of nitrogen in \(Pb(NO_{3})_{2}\) is
+2
+3
+4
+5

Explanation

\(Pb(NO_{3})_{2}\) = \(+2 +2N + (-2\times 6) = 0\)

= \(2N = 10\)

⇒ \(N = +5\)

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