WAEC - Chemistry (2012 - No. 16)
The number of sulphur atoms in 3.20g of SO\(_{2(g)}\) is [O = 16.0;S = 32.0; Avogadro constant = 6.02 x 10\(^{23}\)]
3.01 x 1022
6.02 x 1022
6.02 x1023
1.20 x 1024
Explanation
32g of sulphur = 64g / 6.02 x 10\(^{23}\) atoms of SO\(_2\)
xg of sulphur = 3.2g of SO\(_2\)
: 1.6g of sulphur is present in 3.2g / 3.01 x 10\(^{23}\) atoms of SO\(_2\)
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