WAEC - Chemistry (2009 - No. 17)

How many molecules are there in 14 g of nitrogen at s.t.p.? [N = 14, Avogadro's constant = 6.02 x 10\(^{23}\) mol-1]
6.02 x 1023
3.01 x 1023
8.43 x 1024
1.20 x 1024

Explanation

Given:

mass, m = 14g

Molar mass of N\(_2\) = 14 X 2 = 28g/mol

number of moles, n = ?

But n = \(\frac{m}{M}\) = \(\frac{14}{28}\) 

 n = 0.5 mole

Also, recall that Number of moles = \(\frac{Number of Molecules}{Avogadro number}\)

  n  = \(\frac{N}{L}\)

  N = n x L

 = 0.5 x 6.02 x  10\(^{23}\)

 = 3.01 x 10\(^{23}\) molecules

 

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