Mathematics for IGCSE & O level - Vectors (Section 1 - No. 41)
If \( \vec{a} = egin{pmatrix} 3 \\ 1 \end{pmatrix}\), and \( \vec{b} = egin{pmatrix} -2 \\ 2 \end{pmatrix}\), calculate 3\(\vec{a}\) - 2\(\vec{b}\).
\(\begin{pmatrix} 5 \\ -1 \end{pmatrix}\)
\(\begin{pmatrix} 13 \\ -1 \end{pmatrix}\)
\(\begin{pmatrix} 13 \\ -7 \end{pmatrix}\)
\(\begin{pmatrix} 5 \\ -7 \end{pmatrix}\)
Explanation
3a - 2b = 3 * \(\begin{pmatrix} 3 \\ 1 \end{pmatrix}\) - 2 * \(\begin{pmatrix} -2 \\ 2 \end{pmatrix}\) = \(\begin{pmatrix} 9 \\ 3 \end{pmatrix}\) - \(\begin{pmatrix} -4 \\ 4 \end{pmatrix}\) = \(\begin{pmatrix} 13 \\ -1 \end{pmatrix}\)
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