Mathematics for IGCSE & O level - Vectors (Section 1 - No. 34)
If the position vector of point A is \(\begin{pmatrix} 4 \\ 1 \end{pmatrix}\), and the position vector of point B is \(\begin{pmatrix} 1 \\ 5 \end{pmatrix}\), then \(\vec{AB}\) is:
\(\begin{pmatrix} 5 \\ 6 \end{pmatrix}\)
\(\begin{pmatrix} -3 \\ 4 \end{pmatrix}\)
\(\begin{pmatrix} 3 \\ -4 \end{pmatrix}\)
\(\begin{pmatrix} 5 \\ -4 \end{pmatrix}\)
Explanation
\(\vec{AB} = \vec{OB} - \vec{OA} = \begin{pmatrix} 1 \\ 5 \end{pmatrix} - \begin{pmatrix} 4 \\ 1 \end{pmatrix} = \begin{pmatrix} -3 \\ 4 \end{pmatrix}\)
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