Mathematics for IGCSE & O level - Mensuration (Section 3 - No. 35)
The radius of Jupiter is 7.14 x 10^4 km. Find the surface area of Jupiter.
6.39 x 10^10 km²
6.39 x 10^9 km²
5.5 x 10^10 km²
5.5 x 10^9 km²
Explanation
Surface Area = 4πr². Surface Area ≈ 4π(7.14 x 10^4)² km² ≈ 6.39 x 10¹⁰ km²
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