Mathematics for IGCSE & O level - Limits Of Accuracy (Section 3 - No. 40)
A bar of gold is a cuboid and measures 8.6 cm by 4.1 cm by 2.4 cm. All the measurements are correct to the nearest millimetre. Calculate the greatest possible volume of the gold bar.
85.17 cm³
85.18 cm³
85.19 cm³
85.20 cm³
Explanation
For the greatest possible volume, multiply the upper bounds together. The upper bounds are 8.65 cm, 4.15 cm and 2.45 cm. Volume = 8.65 x 4.15 x 2.45 = 87.834 cm³. (Rounded to 3 s.f, 87.8 cm³)
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