JEE Advance - Physics (2021 - Paper 1 Online - No. 7)
In the circuit shown below, the switch S is connected to position P for a long time so that the charge on the capacitor becomes q1 $$\mu$$C. Then S is switched to position Q. After a long time, the charge on the capacitor is q2 $$\mu$$C.
The magnitude of q1 is ________________.
The magnitude of q1 is ________________.
Answer
1.33
Explanation
Switch connected to position P
$${V_A} - 1\,.\,{i_1} - 1 + 2 - 2{i_1} = {V_A}$$
$$3{i_1} = 1$$
$${i_1} = {1 \over 3}A$$
Now, $${V_A} - 1\,.\,{i_1} - 1 = {V_B}$$
$${V_A} - {V_B} = 1 + {i_1} = {4 \over 3}V$$
Potential drop across capacitor, $$\Delta V = {4 \over 3}V$$
$$\therefore$$ Charge on capacitor, $${q_1} = C\Delta V = 1 \times {4 \over 3}\mu C$$
$${q_1} = 1.33\mu C$$
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