JEE Advance - Physics (2013 - Paper 2 Offline - No. 8)

A steady current I flows along an infinitely long hollow cylindrical conductor of radius R. This cylinder is placed coaxially inside an infinite solenoid of radius 2R. The solenoid has n turns per unit length and carries a steady current I. Consider a point P at a distance r from the common axis. The correct statement(s) is(are)
In the region 0 < r < R, the magnetic field is non-zero.
In the region R < r < 2R, the magnetic field is along the common axis.
In the region R < r < 2R, the magnetic field is tangential to the circle of radius r, centred on the axis.
In the region r > 2R, the magnetic field is non-zero.

Explanation

We know that

(i) For a cylinder, B = 0 for 0 < r < R and $$B = {{{\mu _0}} \over {4\pi }} \times {{2I} \over r}$$ for r > R.

(ii) For a solenoid, B = $$\mu$$0nI for 0 < r < R and B = 0 for r > R.

JEE Advanced 2013 Paper 2 Offline Physics - Magnetism Question 25 English Explanation

$$\bullet$$ Assuming that the magnetic induction to be BC for cylinder and BS for solenoid.

In the region R > r > 0, BS = $$\mu$$0nI while BC = 0. Therefore, the total field is non-zero.

Hence, option (A) is correct.

$$\bullet$$ In the region 2R < r < R, the magnetic field is not along the axis of cylinder which is given as

$$B = \sqrt {B_S^2 + B_C^2} $$

Hence, option (B) is wrong.

$$\bullet$$ For checking option (C), in the region R < r < 2R, the magnetic field is tangential to the circle of radius r, centred on the axis. So this statement is wrong because magnetic field is not in the plane of circle.

Hence, option (C) is wrong.

$$\bullet$$ In the region r > 2, BS = 0; while $${B_C} = {{{\mu _0}} \over {4\pi }} \times {{2I} \over r}$$. Therefore total field is non-zero.

Hence, option (D) is correct.

Comments (0)

Advertisement