JEE Advance - Physics (2013 - Paper 2 Offline - No. 8)
Explanation
We know that
(i) For a cylinder, B = 0 for 0 < r < R and $$B = {{{\mu _0}} \over {4\pi }} \times {{2I} \over r}$$ for r > R.
(ii) For a solenoid, B = $$\mu$$0nI for 0 < r < R and B = 0 for r > R.
$$\bullet$$ Assuming that the magnetic induction to be BC for cylinder and BS for solenoid.
In the region R > r > 0, BS = $$\mu$$0nI while BC = 0. Therefore, the total field is non-zero.
Hence, option (A) is correct.
$$\bullet$$ In the region 2R < r < R, the magnetic field is not along the axis of cylinder which is given as
$$B = \sqrt {B_S^2 + B_C^2} $$
Hence, option (B) is wrong.
$$\bullet$$ For checking option (C), in the region R < r < 2R, the magnetic field is tangential to the circle of radius r, centred on the axis. So this statement is wrong because magnetic field is not in the plane of circle.
Hence, option (C) is wrong.
$$\bullet$$ In the region r > 2, BS = 0; while $${B_C} = {{{\mu _0}} \over {4\pi }} \times {{2I} \over r}$$. Therefore total field is non-zero.
Hence, option (D) is correct.
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