JEE Advance - Physics (2013 - Paper 2 Offline - No. 16)
The correct statement is
the nucleus $$_3^6Li$$ can emit an alpha particle.
the nucleus $$_{84}^{210}Po$$ can emit a proton.
deuteron and alpha particle can undergo complete fusion.
the nuclei $$_{30}^{70}Zn$$ and $$_{34}^{82}Se$$ can undergo complete fusion.
Explanation
We have
$$m(_1^2H) + m(_2^4He) = 2.014102 + 4.002603 = 6.016705\,u$$
$$m(_3^6Li) = 6.015123\,u$$
$${m_1} + {m_2} > M$$
Thus, option (A) is wrong.
$$m(_1^1H) + m(_{83}^{209}Bi) = 1.007825\,u + 208.980388\,u = 209.988213\,u$$
$$m(_{84}^{210}Po) = 209.982876\,u$$
$${m_1} + {m_2} > M$$
Thus, option (B) is wrong.
$$m(_1^2H) + m(_2^4He) = 2.014102\,u + 4.002603\,u = 6.016705\,u$$
$$_3^6Li = 6.015123\,u$$
$$({m_3} + {m_4}) > M'$$
Thus, option (C) is correct. Therefore, deuteron and alpha particle can go complete fusion.
$$m(_{30}^{70}Zn) + _{34}^{82}Se = 69.925325\,u + 81.916709\,u = 151.842034\,u$$
$$_{64}^{152}Gd = 151.919803\,u$$
$${m_3} + {m_4} < M'$$
Thus, option (D) is wrong.
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